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-8x^2-3x+49=0
a = -8; b = -3; c = +49;
Δ = b2-4ac
Δ = -32-4·(-8)·49
Δ = 1577
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{1577}}{2*-8}=\frac{3-\sqrt{1577}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{1577}}{2*-8}=\frac{3+\sqrt{1577}}{-16} $
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